X^2+55x-600=0

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Solution for X^2+55x-600=0 equation:



X^2+55X-600=0
a = 1; b = 55; c = -600;
Δ = b2-4ac
Δ = 552-4·1·(-600)
Δ = 5425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{5425}=\sqrt{25*217}=\sqrt{25}*\sqrt{217}=5\sqrt{217}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-5\sqrt{217}}{2*1}=\frac{-55-5\sqrt{217}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+5\sqrt{217}}{2*1}=\frac{-55+5\sqrt{217}}{2} $

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